-x^2-10X+3000=0

Solution for -x^2-10X+3000=0 equation:

-x^2-10x+3000=0

We add all the numbers together, and all the variables

-1x^2-10x+3000=0

a = -1; b = -10; c = +3000;
Δ = b2-4ac
Δ = -102-4·(-1)·3000
Δ = 12100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12100}=110$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-110}{2*-1}=\frac{-100}{-2}
=+50
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+110}{2*-1}=\frac{120}{-2}
=-60
$